mensuration area volumes Model Questions & Answers, Practice Test for ibps po prelims 2023
ibps po prelims 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Surds & Indices
Ratio & Proportion
Profit & Loss
Time & Work
Simple Interest & Compound Interest
Mensuration: Area & Volumes
In the figure given below, what is the sum of the angles formed around A, B, C except the angles of the ΔABC?
![mensuration area and volume aptitude mcq 22 48](https://careericons.com/adminicon/bunch/images/mensuration-area-and-volume-aptitude-mcq-22-48.png)
Answer: (a)
∠A = 360° – Ext ∠A. ....(i)
∠B = 360 – Ext ∠B .... (ii)
∠C = 360 – Ext ∠C .... (iii)
A B C .
Similarly,
∠A + ∠B + ∠C =180°
From Eqs. (i), (ii), (iii) and (iv),
360° – Ext ∠A +360° – Ext ∠B + 360° – Ext ∠C = 180°
⇒ Ext ∠A +Ext ∠B +Ext ∠C
= 1080° – 180°
= 900°
A solid cone of height 8 cm and base radius 6 cm is melted and recast into identical cones, each of height 2 cm and radius 1 cm. What is the number of cones formed?
Answer: (a)
Volume of bigger cone
= $1/3 π(6)^2 × 8 = 96 π cm^3$
Volume of smaller cone = $1/3 π (1)^2 × 2$
= ${2π}/3 cm^3$
Number of cones = ${96 π}/{{2π}/3}$ = 144
The three sides of a triangle are 10, 100 and x. Which one of the following is correct?
Answer: (c)
We know that, the sum of two sides is always greater than third side.
∴ 10 + 100 > x ...(i)
x > 100 – 10 and x > 90 ...(ii)
Difference of two sides of a triangle is always less than third side.
From Eqs. (i) and (ii),
we get,
90 < x < 110
A rectangular tank whose length and breadth are 2.5 m and 1.5 m, respectively is half full of water. If 750 L more water is poured into the tank, then what is the height through which water level further goes up?
Answer: (b)
Increase in the height of water level
= ${0.75}/{2.5 × 1.5}$m = 0.2 m = 20 cm
A solid metallic cylinder of height 10 cm and radius 6 cm is melted to make two cones in the ratio of volume 1 : 2 and of same height as 10 cm. What is the percentage increase in the flat surface area ?
Answer: (c)
Volume of solid metallic cylinder = π $r^2$h
= π × 36 × 10 = 360 π
flat surface area of cylinder = 2π $r^2$
= 2 × π × 6 × 6 = 72π
After melted to make two cones in the ratio of volume 1 : 2
volume of first cone = $1/3 π r_1^2h$ = 120π
$r_1^2$h = 360
∴ $r_1^2$ = 36
volume of second cone = $1/3 π r_2^2h$ = 240 π
$r_2^2h$ = 720
∴ $r_2^2$ = 72
Flat surface area of two cone = 72p + 36p = 108p
Change in surface = 108π – 72π = 36π
% change = ${36 π}/{72 π}$ × 100 = 50%
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